In the circuit shown in figure, =4.5 V, =9.0 V, R_1=80 ohm, and R_2=40 ohm. Indi
ID: 1491826 • Letter: I
Question
In the circuit shown in figure, =4.5 V, =9.0 V, R_1=80 ohm, and R_2=40 ohm. Indicate the directions of currents i_1, i_2 and i_3 through resistors R_1, R_2 and section be of the circuit, respectively. Write the Kirchhoff's junction rule for point b. Write Kirchhoff's law for loop abcda of the circuit with your choice for the direction of currents in part (a). Write Kirchhoff's law for befcb loop of the circuit with your choice for the direction of currents in part (a). Calculate the current i_1 through the resistance 1. What is the direction of the current (up or down) through the resistance 1? Calculate the current i_2 through the resistance 2. What is the direction of the current (left or right) through resistance 2? What is the potential difference V_ad=V_a-V_d between points a and d? What is the potential difference V_ab=V_a-V_b between points a and b? What is the total power P supplied by both batteries?Explanation / Answer
Here, E1 = i1 * R1 + (i1 + i2) * R2
Also, E2 = - i1 * R1
Also, i1 + i3 = i2
=> 9 = - i1 * 80
=> i1 = - 0.1125 A
=> i2 = 0.45 A
=> current through resistance R1 = 0.1125 A (direction = downwards)
=> current through resistance R2 = 0.3375 A ( direction = leftwards)
Here, Vad = - 4.5 V
Here, Vab = - 0.3375 * 40 = - 13.5 V
total power supplied by batteries = 4.5 * 0.3375 + 9 * 0.45
= 5.568 W