In the circuit shown in Figure, the resistances are R1 = 13 Ohms, R2 = 49 Oms, R
ID: 2278706 • Letter: I
Question
In the circuit shown in Figure, the resistances are R1 = 13 Ohms, R2 = 49 Oms, R3 = 92 Ohms. An ideal ohmmeter is connected across ab with the switch S open. All the connecting leads have negligible resistance. What will be the reading of the ohmmeter (with one decimal place)? Please show work! please and thank you!
In the circuit shown in Figure, the resistances are R1 = 13 Ohms, R2 = 49 Oms, R3 = 92 Ohms. An ideal ohmmeter is connected across ab with the switch S open. All the connecting leads have negligible resistance. What will be the reading of the ohmmeter (with one decimal place)?Explanation / Answer
R1 parallel R3 = 1/(1/13 + 1/92) = 11.39
This combo parrallel R2 = 1/(1/49 + 1/11.39) = 9.242
Now 10 and 20 ohm are in parallel .Therefore R = 9.242 + 10 + 20 = 39.242
Potential difference between this combo is V accross battery
So Current in this combo = V / (39.242)
Therefore potential difference drop across 20+10 = I * R = 30 * V/39.242 = 0.764V
POtential across ab = 0.764V