In figure 19.26, there is a uniform magnetic field of magnitude B=2.3T ... For f
ID: 1382320 • Letter: I
Question
In figure 19.26, there is a uniform magnetic field of magnitude B=2.3T ...
For full points you must show me a thorough, explicit answer. Define all variables and equations. Thanks!
In Figure 29.26, there is a uniform magnetic field of magnitude B = 2.3 T and directed into the plane of the paper in the region shown. Outside this region the magnetic field is zero. A rectangular loop 0.20 m by 0.60 m and of resistance 8 ohm is being pulled into the magnetic field by an external force, as shown. What is the direction (clockwise or counterclockwise) of the current induced in the loop? Calculate the magnitude of the external force Fext required to move the loop at a constant speed of v = 3.9 m/s. The mass of the loop is 0.008 kg.Explanation / Answer
Explanation : As the loop moves right side the magnetic flux through(into the page) increases. so, emf is induced and induced current flows.
According to Lenz's law this induced current always opposes the cause of which generated the induced current.
so magnetic flux produced by tis induced current should be out of the page.so, Cirrent direction direction should be counet clockwise.
b) induced emf = B*v*L
v --> speed of rod
B ---> magetic filed
L --> length of reactangular(perpedicular ot the motion of the loop)
induced current = B*v*L/R
power required, F*v = emf*current
F*v = (B*v*L)*(B*v*L/R)
F = B^2*L^2*v/R
= 2.3^2*0.2^2*3.9/8
= 0.103 N <<<<<<<------------Answer