Consider the system pictured in the figure below. A ? = 13-cm length of conducto

Question

Consider the system pictured in the figure below. A ? = 13-cm length of conductor of mass 11 g, free to move vertically, is placed between two thin, vertical conductors, and a uniform magnetic field acts perpendicular to the page. When a 5.0-A current is directed as shown in the figure, the horizontal wire moves upward at constant velocity in the presence of gravity.

(a) What forces act on the horizontal wire, and under what condition is the wire able to move upward at constant velocity?

Score: 1 out of 1

Comment:

(b) Find the magnitude and direction of the minimum magnetic field required to move the wire at constant speed.

(c) What happens if the magnetic field exceeds this minimum value? (The wire slides without friction on the two vertical conductors.)

magnitude       
Your response differs from the correct answer by more than 10%. Double check your calculations. T direction     ---Select--- left up out of the page down right into the page

Explanation / Answer

a)

here , magnetic force and gravity acts on the rod .

for rod to move at constant velocity ,

Gravity = mgnetic force

b)

B*I*L = m*g

B*5 * 0.13 = 0.011 * 9.8

B = 0.166 T

the magnetic field is 0.166 T

the field must be out of the page

c)

if the value of magnetic field is greater than this value ,

the magnetic force will be higher and the rod will accelerating in upwards direction

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---