In the figure, determine the character of the collision. The masses of the block
ID: 1384324 • Letter: I
Question
In the figure, determine the character of the collision. The masses of the blocks, and the velocities before and after are given, and no other unbalanced forces act on these blocks. The collision is
In the figure, determine the character of the collision. The masses of the blocks, and the velocities before and after are given, and no other unbalanced forces act on these blocks. The collision is
-not possible because momentum is not conserved. -partially inelastic. -completely inelastic. -characterized by an increase in kinetic energy. -perfectly elastic.Explanation / Answer
befor collision
initial momentum of the system = m1*v1 + m2*v2
Pi = (9*2.1)-(3*0.6) = 17.1 kg m/s
after collison
final momentum of the system Pf = m1*v1' + m2*v2'
Pf = (9*1.5)+(3*1.5) = 18 kg m/s
here initial momentum is not equal to final momentum
the conservation law is not obeyed
so this collision is not possible
-not possible because momentum is not conserved