Physics 2. Need help ASAP. A parallel-plate capacitor with a capacitancc of C =

Question

Physics 2. Need help ASAP. A parallel-plate capacitor with a capacitancc of C = 5.5 muF is completely charged using a battery The capacitor is then disconnected from the circuit and electrically isolated. Your friend fills the space between the plates with a dielectric material of K = 2.1. You measure the potential difference between the plates to be 8.3 V. What was the potential difference of the batter) used to charge the capacitor and how much charge is on the plates when you measure the potential difference? Given two metal spheres, initially far apart, one with a radius of 6 cm and the other a radius of 12 cm. You place 7.0 muC of charge on the smaller sphere and 3.0 muC on the other. You then electrically connect the spheres, disconnecting them a long time later. How much charge is on each sphere alter disconnecting them? Explain briefly:

Explanation / Answer

Here ,

as when the dielectic is inserted ,

Ceq = 5.5 * 2.1

Ceq = 11.55 uF

now, charge on capacitor , Q = 11.55 * 8.3 = 95.9 uC

now, initially ,

11.55 * 8.3 = 5.5 * V

V = 17.43 V

the charge on the capacitor is 95.9 uC

and voltage of battery is 17.43 V

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