Physics 17-1 (PHY1025) Newton\'s Laws Chapter 5: Force and Newton\'s Laws Sectio
ID: 1785021 • Letter: P
Question
Physics 17-1 (PHY1025) Newton's Laws Chapter 5: Force and Newton's Laws Section 2: Newton's first law 5.2.1 An airplane of mass 2867 kg flies at a constant horizontal velocity The force (1.00) of air resistance on it is 2225 N. What is the net force on the plane (magnitude and direction)? oz suomissions used 0 N (direction does not matter) Se 5 2225 N opposing the motion ight 5.4.2 642 N at 30° below horizontal (1.00) It is impossible to say weigh on the Earth? (b) How much = 0.166g)? (c) How much would she ut weigh on a neutron star where gstar - 143*1011g'? (012 submissions used) N (012 submissions used) N (0/2 submissions used)Explanation / Answer
5.2.1 as the velocity is constant so net acceleration is zero and so force = mass * acceleration is also zero
0 N (direction does not matter)
5.4.2
(a) weight on earth = mg = 70 * 9.807 = 686.5 N
(b) weight on moon = m gmoon = 70 * 0.166 * g = 70* 0.166*9.807 = 113.96 N
(c) weight on neutron = m gstar = 70 * 1.43*10^11 * 9.807 = 9.817 * 1013 N
5.5.2
m = 0.125 kg
(a) net force = 0.800 acting right +(- 2.30)acting left so negative = 0.800 - 2.3 = - 1.5 N
(b) acceleration = F/m = -1.5/0.125 = -12 m/s2