Physics 110 Fall 2015 Workout 2(30 points) Two barges have a collsion. Barge A h
ID: 1791770 • Letter: P
Question
Physics 110 Fall 2015 Workout 2(30 points) Two barges have a collsion. Barge A has a mass of 110,000 kg and is traveling with a velocity = 0.15 Barge B has a mass of 150,000 kg and is traveling with a velocity0.24 + 009, J. After the collision Barge A has a velocity = 0.10 0.06 t. [15 points] What is the final velocity of the Barge B? Barge A Barge B [12 points]What was the change in energy and change in momentun due to the collision? (3 points] What type of collision was it? Justify your answerExplanation / Answer
a] By momentum conservation,
mAVai + mB Vbi = mA Vbf + mBVbf
110000*0.15i + 150000*-0.24 i + 150000*0.09 j = 110000*0.10 i + 110000*0.06j + 150000 Vbf
Vbf = (110000*0.15 - 150000*0.24-110000*0.10)/150000 i + (150000*0.09-110000*0.06)/150000
= -0.203 m/s i + 0.046 j m/s answer
b] change in energy = final KE - initial KE
= 0.5*110000*(0.10^2+0.06^2) +0.5*150000*(0.2033^2+0.046^2) -[0.5*110000*0.15^2 +0.5*150000*(0.24^2+0.09^2)]
= -2158 J
MOMENTUM CHANGE = 0 as it is conserved.
c] Since energy is decreased, it is inelastic collision.