Partial credit for: providing the formulas needed in each section and the values

Question

Partial credit for: providing the formulas needed in each section and the values of the various mantities in those formulas; correctly identifying the relevant forces (magnitude and direction); mj drawing diagrams (e.g., free-body diagrams, initial/final configuration for energy/momentum nservation, ...). A 75-kg man lies on a 2-m-long light (massless) board which is supported by a scale and a leg, as shown in the figure. The scale reads, kg. What distance is the center of gravity of this person from the leg that supports the board?

Explanation / Answer

take center of gravity from leg end support = x

take moment about leg end

40 g * 2 = x * 75 g

x = 80/75 = 1.067 m

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