A small 0.300kg bird is flying horizontally at 3.50m/stoward a 0.750kg thin bar
ID: 1394501 • Letter: A
Question
A small 0.300kg bird is flying horizontally at 3.50m/stoward a 0.750kg thin bar hanging vertically from a hook at its upper end, as shown in the figure below (Figure 1)
Part A
When the bird is far from the bar, what are the magnitude and direction (clockwise or counterclockwise) of its angular momentum about a horizontal axis perpendicular to the plane of the figure and passing through point A?
L = kg?m2/s
Part B
When the bird is far from the bar, what are the magnitude and direction (clockwise or counterclockwise) of its angular momentum about a horizontal axis perpendicular to the plane of the figure and passing through point B?
L = kg?m2/s
Part C
When the bird is far from the bar, what are the magnitude and direction (clockwise or counterclockwise) of its angular momentum about a horizontal axis perpendicular to the plane of the figure and passing through point C?
L = kg?m2/s
Part D
When the bird is just ready to hit the bar, but is still flying horizontally, what are the magnitude and direction (clockwise or counterclockwise) of its angular momentum about a horizontal axis perpendicular to the plane of the figure and passing through point A?
L = kg?m2/s
Part F
When the bird is just ready to hit the bar, but is still flying horizontally, what are the magnitude and direction (clockwise or counterclockwise) of its angular momentum about a horizontal axis perpendicular to the plane of the figure and passing through point C?
L = kg?m2/s
Let counterclockwise angular momentum be positive, clockwise angular momentum be negative. For all Problems listed above.
Please show work.
Explanation / Answer
Answer
PART- A
angular momentum = linear momentum * normal (perpendicular) distance to the line of motion:
Linear momentum = 0.300*3.50
distance to A = 1.50 m
angular momentum = 1.58 kg*m