In the system shown in the figure below, a horizontal force F acts on an object

Question

In the system shown in the figure below, a horizontal force F acts on an object of mass m2 = 7.40 kg. The horizontal surface is frictionless. Consider the acceleration of the sliding object as a function of Fx. (a) For what values of Fx does the object of mass m1 = 3.50 kg accelerate upward? (Indicate the direction of the force with the sign of your answer. Let the positive x direction be to the right.) Fx> Your response differs from the correct answer by more than 10%. Double check your calculations. N (b) For what values of Fx is the tension in the cord zero? (Indicate the direction of the force with the sign of your answer. Let the positive x direction be to the right.) Fx

Explanation / Answer

here,

let the tension in the string is t N

(a)

m2 = 7.4 kg

m1 = 3.5 kg

from the figure shown, for equilibriun

t = m1*g ......(1)

for accelration upwards

Fx = t = m1 * g

Fx = 3.5 * 9.8

Fx = 34.3 N

Fx > 34.3 N to accelrate the object of mass m1

(b)

for tension in the cord to be zero ,

the accelration of both the masses should be equal

so ,

Fx = m2 * g

Fx = 7.4 * 9.8

Fx = 72.52 N

for the tension in the cord is zero , Fx < = -72.52 i.e the force is in negative x direction

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