The diagram shows a simple pendulum consisting of a mass M suspended by a thin s
ID: 1395971 • Letter: T
Question
The diagram shows a simple pendulum consisting of a mass M suspended by a thin string. The magnitude of the tension is T. The mass swings back and forth between +-theta 0 (Give ALL correct answers in alphabetical order, i.e., B, AC, BCD...). A) T equals Mg when theta =theta 0 . B) T is smallest when theta =+-theta 0. C) T is greater than Mg for theta =theta 0 . D) T=Mg at some angle between zero and theta 0 . E) T is largest at the bottom theta = 0 . F) T depends on theta. G) The vertical component of tension is constant. Yes, Computer gets: BDEF 19. If for the simple pendulum above, M=1.39kg, the length of the string=0.910m, and +-theta 0=53.5 degree, find the maximum kinetic energy of the mass during an oscillation. Answer:Explanation / Answer
BDEF
The body gets maximum kinetic enrgy at its lowest point.
Apply Conservation of enrgy,
gain in kinetic enrgy = loss in potential enrgy
KEmax = m*g*h (here h is diffrence hight at the pendulum moves from extrme point to lower point)
= m*g*L*(1 - cos(theta0))
= 1.39*9.8*0.91*(1 - cos(53.5))
= 5.02 J