For the R12 R2 circuit shown R7 R1- R3 R9 R11 R13 69.0 Ohms, R5 the rest of R13

Question

For the R12 R2 circuit shown R7 R1- R3 R9 R11 R13 69.0 Ohms, R5 the rest of R13 the R8 R4 resistors are 138.0 Ohms a) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in series SUBMIT b) Without doing any simplification (or combination) identify the number of pairs of resistors (that is 2 resistors) that are in parallel SUBMIT c) Find R67 the equivalent resistance of resistors R6, and R7 SUBMIT d) Knowing that R12345 the equivalent resistance of resistors R1, R2. R3, R4 and R5 is equal to R12345 79.9 ohms, Find R1234589 the equivalent resistance of resistors R 12345, R8, and R9 SUBMIT e) Find R12345678910 the equivalent resistance of all resistors except R11, R12 and R13

Explanation / Answer

a) 1 . R1 and R2

b) 1 . R6 and R7

c)

R6 and R7 are in parallel and their parallel combination is given as ::

R67 = R6 R7 / (R6 + R7)

R67 = 138 x 138 / (138 + 138)

R67 = 69 ohm

d)

R12345 and R8 are in series and their series combination is given as ::

R123458 = R12345 + R8 = 79.9 + 138 = 217.9 ohm

R123458 and R9 are in parallel and their parallel combination is given as ::

R1234589 = R123458 R9 / (R123458 + R9)

R1234589 = (217.9) (69) / (217.9 + 69)

R1234589 = 52.41 ohm

e)

R1234589 and R67 are in series

R123456789 = R1234589 + R67 = 52.41 + 69 = 121.41 ohm

R123456789   and R10 are in parallel

R12345678910 = R123456789 R10 / (R123456789 + R10)

R12345678910 = 121.41 x 138 / (121.41 + 138) = 64.6 ohm

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---