An infinitely long, straight conductor consists of of an inner cylindrical condu
ID: 1399862 • Letter: A
Question
An infinitely long, straight conductor consists of of an inner cylindrical conductor of radius
R which carries a uniform current I0. This conductor is surrounded bv a second, coaxial
conductor of inner radius R and outer radius 2R. Through this outer conductor flows a
uniform current of 2I0, with a direction that is opposite to the one in the central conductor'.
Calculate the magnetic field strength B for the following distances from the center of the
conductor:
a)r>2R
b) R <r <2R
c)r<R
Explanation / Answer
a) at r > 2*R
Apply,
integral B*dl = mue*I_enclosed
B*2*pi*r = mue*(2*Io - Io)
B = mue*Io/(2*pi*r) <<<<<---------Answer
b) R <r <2R
Apply,
integral B*dl = mue*I_enclosed
B*2*pi*r = mue*(2*Io*(r^2 - R^2)/(2*R)^2 - Io)
= mue*Io*((r^2 - R^2)/(2*R^2) - 1 )
B = mue*Io*((r^2 - R^2)/(2*R^2) - 1 )/(2*pi*r) <<<<<---------Answer
c) at r< R
Apply,
integral B*dl = mue*I_enclosed
B*2*pi*r = mue*Io*(r^2/R^2)
B = mue*Io*r/(2*pi*R^2) <<<<<---------Answer