I need help with these asap! Fireex File Edit View History Bookmarks Tools windo

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I need help with these asap! Fireex File Edit View History Bookmarks Tools window Help 0400 55% Ba, wlod 7:54:40 PM gonEr2 Problem 23.41: Reversbaty of rays previousl 10of14 1 next » Problem 23.41: Reversibility of rays Part A Ray 1 of light in medium A (see the figure (Fiaure 1)) strins the surface at 51.0°wit resped to he normal. Show that the angle of refraction of ray 1 with respect to the normal in medium B s358" Essay answers are limited to about 500 words (3800 characters maximum, Including spaces). 3800 Charscter(s) remaining My Answers Give Up Part B Now suppose that ray 2 is the reverse of ray 1, so that iR strikes the surface at 35.8 with the normal in B. Show that ray 2 will oome out in A at 51.0 with the normal. In other words, show hat rays 1 and 2 fallow the same path, except reversed from each other Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining 125 My Answers h

Explanation / Answer

part a ) using snell law

n1sint1 = n2sint2

n1 = 1.25

n2 = 1.66

sint1 = 51

sint2 = n1sint1 / n2

sint2 = 1.25 x sin51 /1.66

t2 = sin^-1( 1.25 x sin51 /1.66 ) = 35.8 degree

part b )

use snell law again

n1sint1 = n2sint2

n1 = 1.66 sint1 = 35.8

n2 = 1.25

sint2 = n1sint1/n2

t2 = sin^-1( 1.66 x sin35.8 /1.25)

t2 = 51 degree

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