In the circuit shown below, the elements have the following values: ?=24.0V, R1
ID: 1412425 • Letter: I
Question
In the circuit shown below, the elements have the following values: ?=24.0V, R1 =5.00k?, R2 =10.00k?, and L=0.60H.
To start, the switch has been closed for a long time and steady state conditions have been established.
a) What is the steady state current in R1?
b) What is the steady state current in R2?
The switch is then opened at t = 0. (The opened switch is shown in the diagram.)
c) What is the emf across the inductor immediately after the switch is opened? Be sure to indicate which end of the inductor (a or b) is at the higher potential.
d) Draw a qualitative graph showing the current in R1 (starting from t = 0).
e) Draw a qualitative graph showing the current in R2 (starting from t = 0).
f) Once the switch is opened, how long does it take for the current in R2 to reach a value of 1.00 mA?
Explanation / Answer
a) in start ...since the circuit reaches the steady state impies that inductor will behave as connecting wire
now analizing the circuit both the resistors R1 and R2 are in parallel so net resistance of the circuit is r=R1 * R2/(R1+R2) =10*5/(10+5)=10/3.
steady state current in R1=v/R= 24/5.
b) steady state current in R2 =24/10