In the circuit shown below, the current in the central branch is I2 = 1.3 A. App

Question

In the circuit shown below, the current in the central branch is I2 = 1.3 A. Apply Kirchoff's rules and the junction rule to determine three equations that can be used in the next step to determine the currents. Determine the currents in the left and right branches of the circuit using your results for part Determine the potential difference Va-Vb. At what rate is energy being delivered to the circuit by the 15 V battery. For the circuit depicted below apply Kirchoff's rules to answer the questions.

Explanation / Answer

a) consider positive currents up

so I1 +I3 = I2 = 1.3

left loop

-10 I1 + 10 - 10*1.3 + 15 = 0

right loop

-10*1.3 + 15 - 20*I2 = 0

b) I left = I1= 1.2 A up

I right = 0.1 A

c) Va + 10 - I right * 10 = Vb

Va - Vb = - 10 + I right*10 = -10 + 1 = -9

D) P battery = I battery V battery = 1.3*15 = 19.5 W

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