In the circuit shown on the right, the elements have the following values: ? = 2
ID: 1413311 • Letter: I
Question
In the circuit shown on the right, the elements have the following values: ? = 24.0 V, R1 = 5.00 k?, R2 = 10.00 k?, and L = 0.60 H.
To start, the switch has been closed for a long time and steady state conditions have been established.
a) What is the steady state current in R1?
b) What is the steady state current in R2? The switch is then opened at t = 0. (The opened switch is shown in the diagram.)
c) What is the emf across the inductor immediately after the switch is opened? Be sure to indicate which end of the inductor (a or b) is at the higher potential.
d) Draw a qualitative graph showing the current in R1 (starting from t = 0).
e) Draw a qualitative graph showing the current in R2 (starting from t = 0).
f) Once the switch is opened, how long does it take for the current in R2 to reach a value of 1.00 mA?
In the circuit shown on the right, the elements have the following values = 24.0 V, Ri-5.00 kQ, R2 10.00 k(2, and L = 0.60 H To start, the switch has been closed for a long time and steady state conditions have been established. a)What is the steady state current in Ri? b)What is the steady state current in R2? R2 The switch is then opened at t- 0. (The opened switch is shown in the diagram.) c)What is the emf across the inductor immediately after the switch is opened? Be sure to indicate which end of the inductor (a or b) is at the higher potential. d)Draw a qualitative graph showing the current in Ri (starting from t 0) e)Draw a qualitative graph showing the current in R2 (starting from t 0) f)Once the switch is opened, how long does it take for the current in R2 to reach a value of 1.00 mA?Explanation / Answer
a) steady state current in R1 = 24/5000
= 4.8 mA
b) steady state current in R2 = 24/10000
= 2.4 mA
c) emf across inductor = 4.8 * (5)
= 24 V
d) Current in R1 decreases exponential from 4.8 mA to zero .
e) Current in R2 decreases exponential from 2.4 mA to zero .
f) Here, 1/2.4 = e-t/4 * 10-5
=> t = 3.501 * 10-5 sec ----------------> time taken