Refer to the diagram here (not to scale)-and note the coordinate axes. Note also
ID: 1413517 • Letter: R
Question
Refer to the diagram here (not to scale)-and note the coordinate axes. Note also: 0 degree is eastward and 90 degree is upward. A particle of known mass m, initially moving L eastward at an unknown speed enters the space between two charged plates, of known length L, where a uniform electric field exists. After exiting the plates, the particle enters, then exits, a uniform magnetic field of known magnitude B_1. Then it enters the known uniform magnetic field B_2 at a known velocity v_2. As it enters B_2, a known magnetic force F is exerted on the particle. The data: m = 1.50 Times 10^-26 kg L = 23.4 cm B_1 = 56.7 mT B_2 = 89.0 mu T 150 degree v_2 = 3.12 Times 10^5 m/s 25.0 degree F = 7.28 Times 10^-18 N north (All gravitational forces are negligible.) Describe the particle's travel within B_1: At what angle did it exit? At what angle did it enter? How far apart were its entry and exit points? Calculate the total time the particle spent within B_1. (There are two possible paths. Draw both, but find the transit time for just one-just pick one.) Calculate the electric field (magnitude and direction) produced by the plates. Suppose that-instead of entering the plates or doing any of the other travel described above-this particle had just passed (at the velocity v_0 same as above) through the center of a simple circular loop (R = 5.46 cm) carrying a known steady current (I = 7.89 A). If the force exerted on the particle as it passed through the center of the loop was the same as above (F = 7.28 Times 10^-18 N north), in what direction was the loop's normal vector pointing? (There are four possible solutions. Draw all four but calculate just one-just pick one.)Explanation / Answer
Here, Force = q (v X B)
= qvB * sin(theta)
=> qvB * sin(theta) = mv2/r
=> time = (2pi * r)/v
a) angle = 50 degree
far apart = 15 cm
total time = 2 * 10^-3 sec
b) Electric field = 19445 N/C
Direction = 120 degree
c) Direction = 135 degree North