Please help I cannot get answer When a particle of charge q > 0 moves with a vel
ID: 1413562 • Letter: P
Question
Please help I cannot get answer When a particle of charge q > 0 moves with a velocity of v_1 that is at 45.0 degree from the +x-axis in the xy-plane, a uniform magnetic field exerts a force f- along the -x-axis. When the same particle moves with a velocity v_2 with the same magnitude as v_1 but along the +z-axis, a force F? of magnitude F_2 is exerted on It along the +x-axis. What is the magnitude (In terms of q, v_2 and F_2) of the magnetic field? What is the direction of the magnetic field? What is the direction of the magnetic field?Explanation / Answer
F2=qV2B
B= F2/qV2
b)
F1= F2/sqrt2