Use the following scenario for the next two problems. An ice cube at -5.0 degree
ID: 1414010 • Letter: U
Question
Use the following scenario for the next two problems. An ice cube at -5.0 degree C is dropped into a thermally insulated cup holding water at 0.0 degree C. When equilibrium is reached, the temperature of the contents in the cup is -0.20 degree C. The latent heat of fusion for water is 33.5 times 10^4 J/kg, specific heat of water is 4186 J/kg.K, and specific heat of ice is 2090 J/kg.K. What are the contents in the cup when equilibrium is reached? Liquid water Ice A mixture of liquid water and ice with more than half of contents being liquid water A mixture of liquid water and ice with more than half of contents being ice Not enough information is given. What is the ratio of the masses, m_i/m_w where m_i is the initial mass of the ice, and m_w is the initial mass of the water before the ice cube was dropped into the cup? 0.030 0.083 17 33 430Explanation / Answer
Initial Mass of ice, = mi
Initial Mass of water , = mw
Ti = -5.0 oC
Tw = 0.0 oC
Tf = -0.2 oC
Heat Lost by water = Heat gained by ice
mi*Ci*(Tf - Ti) = mw * Cw * (Tf) + mw * Li
mi * 2090 * (-0.2+5.0) = mw * 33.5 * 10^4 + mw * 2090 * 0.2
mi/mw = 335418/10032
mi/mw = 33
(7)
Correct options - (D) A mixture of Liquid water and ice with more than half of contents being ice !!
(8)
Correct options - (D) 33