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ID: 1417044 • Letter: P
Question
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Three point charges lie on the x axis. Charge 1 (+9.3 mu C) is at the origin, charge 2 (-5.5 muC) is at x = 12 cm. and charge 3 (+4.5 muC) is at x = 15 cm. k = 8.99 times 10^9 N middot m^2/C^2. What is the direction of the total force exerted on charge 3? in positive x-direction in negative x-direction the total force is zero What is the magnitude of the total force exerted on charge 3? Express your answer to two significant figures and include the appropriate units.Explanation / Answer
by coulAMB LAW
F=KQaQb/d2
so force on q3
F =8.99*109[{ 9.3*10-6*4.5*10-6/0.152} +{-5.5*10-6*4.5*10-6/0.032} ]
F= 8.99*10-3[{ 9.3*4.5*/0.152} +{-5.5*4.5/0.032} ]
F= 8.99*10-3[1860-27500] = -230.5036N