Consider the following situation: A uniform stick 1.0 m long with a total mass o
ID: 1417333 • Letter: C
Question
Consider the following situation: A uniform stick 1.0 m long with a total mass of 0.270 kg lays on a sheet of ice, assume no friction. A 0.05 kg bullet is shot into the stick midway above the rod's center of mass. The bullet approaches with a speed of 250 m/s, and remains stuck in the rod after the collision. a) What is the angular momentum about the pivot and the linear momentum of the system before the bullet hits the stick? b) Where the bullet hits the stick, where is the center of mass of the bullet+stick system located? c) What is the angular momentum about the pivot and the linear momentum of the system after the bullet hits the stick? d) With what linear velocity does the center of mass of the system have after the collision? e) What is the angular velocity of the system after the collision?Explanation / Answer
a)Angular momentum is 0, Linear momentum is 0.05*250=12.5 Kgm/s.
b) Centre of mass will still be at the same point, i.e halfway the rod and midway in thickness. This is bcoz bullet hits the rod at its centre of mass.
c) Angular momentum is 0, Linear momentum is same as before , i.e 12.5 Kgm/s.
d) Linear velocity = 12.5/(0.27+0.05) =39.0625 m/s
e) zero.