In the figure below, a constant horizontal force F_app of magnitude 10 N is appl
ID: 1418187 • Letter: I
Question
In the figure below, a constant horizontal force F_app of magnitude 10 N is applied to a wheel of mass 14 kg and radius 0.50 m. The wheel rolls smoothly on the horizontal surface, and the acceleration of its center of mass has magnitude 0.43 m/s^2. In unit-vector notation, what is the frictional force on the wheel? Ni What is the rotational inertia of the wheel about the rotation axis through its center of mass? kg m^2 Did you write Newton's second law for the motion along the horizontal axis? (How many horizontal forces act on the wheel?) Did you write Newton's second law for the rotation of the wheel? (How many non-zero torques act on the wheel?) Did you relate the given linear acceleration to the angular acceleration?Explanation / Answer
As, Torque = I * alpha
=> Frictional force * R = I * alpha
b) rotational inertia of wheel = (3.98 * 0.50 * 0.50)/0.43
= 2.314 kg-m2