For such a connection, the current is the same for all individual resistors and
ID: 1421293 • Letter: F
Question
For such a connection, the current is the same for all individual resistors and the total voltage is the sum of the voltages across the individual resistors.
Using Ohm's law (R=VI), one can show that, for a series connection, the equivalent resistance is the sum of the individual resistances.
Mathematically, these relationships can be written as:
I=I1=I2=I3=...
V=V1+V2+V3+...
Req?series=R1+R2+R3+...
An example of a parallel connection is shown in the diagram:
(Figure 2)
For resistors connected in parallel the voltage is the same for all individual resistors because they are all connected to the same two points (A and B on the diagram). The total current is the sum of the currents through the individual resistors. This should makes sense as the total current "splits" at points A and B.
Using Ohm's law, one can show that, for a parallel connection, the reciprocal of the equivalent resistance is the sum of the reciprocals of the individual resistances.
Mathematically, these relationships can be written as:
V=V1=V2=V3=...
I=I1+I2+I3+...
1Req?parallel=1R1+1R2+1R3+...
NOTE: If you have already studied capacitors and the rules for finding the equivalent capacitance, you should notice that the rules for the capacitors are similar - but not quite the same as the ones discussed here.
In this problem, you will use the the equivalent resistance formulas to determine Req for various combinations of resistors.
Part A
For the combination of resistors shown, find the equivalent resistance between points A and B.
(Figure 3)
Express your answer in Ohms.
Part B
For the set-up shown, find the equivalent resistance between points A and B.
(Figure 4)
Explanation / Answer
Part A : Figure 3.
Equivalent resistance = R = R1 +R2 +R3 = 2 + 3 + 4 = 9 ohm
Part A : Figure 4.
Equivalent resistance = R = R1*R2/(R1 +R2) = 6*3/(6 + 3) = 2 ohm