Consider three point charges at the corners of a triangle, as shown in the figur

Question

Consider three point charges at the corners of a triangle, as shown in the figure above, where q1 = 5.93 10-9 C, q2 = -2.05 10-9 C, and q3 = 4.71 10-9 C.

(a) Find the components of the force vector F 23 exerted by q2 on q3.

F23x=N

F23y=N

(b) Find the components of the force vector F 13 exerted by q1 on q3.

F13x = N

F13y=N

(c) Find the resultant force on q3, in terms of components and also in terms of magnitude and direction.

Fx = N

Fy = N

magnitude N

direction ° counterclockwise from the +x-axis

Using the same triangle, find the vector components of the electric force on q1 and the vector'magnitude and direction.

Fx = N

Fy = N

magnitude N

direction ° counterclockwise from the +x-axis

Explanation / Answer

part a:

magnitude of F23=9*10^9*q2*q3/4^2=5.4312*10^(-9) N

it is along -ve x axis.

hence F23x=-5.4312*10^(-9) N

F23y=0

part b:

magnitude of F13=9*10^9*q1*q3/5^2=10.055*10^(-9) N

F13x=F13*cos(36.9)=8.044*10^(-9) N

F13y=F13*sin(36.9)=6.033*10^(-9) N

part c:

total force:

Fx=F23x+F13x=2.6128*10^(-9) N

Fy=F23y+F13y=6.033*10^(-9) N

magnitude=sqrt(Fx^2+Fy^2)=6.5745*10^(-9) N

angle with +ve x axis=arctan(Fy/Fx)=66.5833 degrees

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