The object is the one you move, on the left Its image is on the right. There is

Question

The object is the one you move, on the left Its image is on the right. There is a relationship between the object distance (d_o, distance between object and lens center), image distance (d_i, distance between lens center and image), and focal length of a lens It says that: 1/d_o + 1/d_i = 1/f Measure the initial values of these 3 distances (d_o, d_i, and f) on your screen, and record them below: Using your three measured values above, show that when you plug these values into the formula above, the left side of the equation equals the right side. When the object is outside of the focal length on the left side of the converging lens describe the image [List whether it is upside down or right-side-up real or virtual, and larger or smaller] When the object is inside the focal length of the lens, what type of image would be formed (real or virtual)?

Explanation / Answer

Part C)

for a converging lens , when the object is outside the focal length , the image formed is real , inverted and larger in size.

Part d)

when the object is inside the focal length , then image formed is virtual and larger in size.

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