Consider the circuit shown in the figure below. (Assume R 1 = 12.0 , R 2 = 3.05

Question

Consider the circuit shown in the figure below. (Assume  R1 = 12.0 , R2 = 3.05 , and V = 7.35 V.)

(a) Calculate the equivalent resistance of the R1 and 5.00- resistors connected in parallel.


(b) Using the result of part (a), calculate the combined resistance of the R1, 5.00- and 4.00- resistors.


(c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00- resistor.


(d) Combine the equivalent resistance found in part (c) with the R2 resistor.


(e) Calculate the total current in the circuit.
A

(f) What is the voltage drop across the R2 resistor?
V

(g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00- resistor.
V

(h) Calculate the current in the 3.00- resistor.

Explanation / Answer

a)

for parallel :

Req = (1/12 + 1/5)^-1
Req = 3.5294
b)

for series : 3.5294 + 4 = 7.5294

c)

Req = (1/7.5294 + 1/3)^-1 = 2.1452

d) 2.1452 + 3.05 = 5.1952

e) V=IR

I = V/R = 7.35/5.1952 = 1.4147 A

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