Please show work. Two M = 20-kg masses arc attached by a cord around an ideal pu
ID: 1425674 • Letter: P
Question
Please show work. Two M = 20-kg masses arc attached by a cord around an ideal pulley with the two masses on opposite sides of a double incline as in the figure to the right. The respective angles of inclination on the left & right are 9_L s 53degree & 9_R =37degree. Neglect friction, and take sin 9_L= cos 9_R = 0.6 & cos 9_L = sin 9_R = 0.4 Draw in vectors for each of the forces acting on the left-most mass M. These forces together constitute the net force on this mass. Give these forces single-letter labels. Give brief (~2-word) descriptive names for each of these forces. What is the direction of the normal force on the left-most mass ? What is the magnitude of the normal force on the left-most mass? What is the direction of the acceleration that the left-most mass experiences? What is the common magnitude of accelerations which the two masses undergo?Explanation / Answer
11)
Equations are as below,
M*g*sin(L) - T = M*a -----1
T - M*g*sin(R) = M*a -----2
M*g*sin(L) - (M*a + M*g*sin(R)) = M*a
M*g*( sin(L) - sin(R)) = 2*M*a
10* (0.6 - 0.4) = 2*a
a = 1.0 m/s^2
Direction = Tangentially Down to the Left INCLINE.
(12)
Acceleration, a = 1.0 m/s^2