Solve the following equation F = ma for the quantity a Solve the following equat
ID: 1429778 • Letter: S
Question
Solve the following equation F = ma for the quantity a Solve the following equation PV = nRT for the quantity P. Solve the following equation b(a + c) = dt for the quantity b. Solve the following equation x = st + 1/2(aT^2) for the quantity s. A car moves along a straight so that its position (distance from the starting point varies) With time as described by the graph shown here Does the car ever go backward? Explain. Is the instanteneous velocity at point A greater or less than at point B? Explain. Two balls are rolled off a tabletop that is 2m above the floor. Ball A has a horizontal Speed of 5m/s and that of ball B is 4m/s. Assuming g = 10 m/s^2 how long does it lake each ball to reach the floor after it rolls off the edge ? How far does each ball travel horizontally before hitting the floor? If the two balls started rolling at the same time at a point 3m behind The edge of the table will they reach the floor at the same time?Explanation / Answer
1)
a = F/m
P = nRT/ V
b = dt / (a+c)
s = (X - aT^2 /2)/t
2) Graph missing
3) both balls have initial horizontal velocity.
that mean initial vertical velocity is zero.
and both balls have to go 2m down to reach the floor.
y = uy*t + ay*t^2 /2
-2 = 0 - 10t^2 /2
t = 0.632 s .......same for both balls .....Ans(a)
b) x = vx*t
for A: x = 5 x 0.632 = 3.16 m
for B : x = 4 x 0.632 = 2.53 m
c) time taken from top to bottom of table will be same but there will be some time gap in
rolling 3m distance
for ball A: (3/5) + 0.632 = 1.232 s
for ball B : (3/4) + 0.632 = 1.382 s