Mastering Physics: Ch 26 Homework Google Chrome https:// mastering physics.com V

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Mastering Physics: Ch 26 Homework Google Chrome https:// mastering physics.com View? offset next&assignmentProblemID; 58186274 Session PHY 222 (Spring 2016 Signed in as robert reynolds Help Close Ch 26 Homework Problem 26.2 Resources previous l 2 of 12 l next Problem 26.2 Part A The balls in the figure are charged to 5.6 nC. What are Specify the strength of the electric field. the strength and direction of the electric field at the Express your answer using two significant figures position indicated by the dot in the figure? (Figure 1) N/C Submit My Answers Give Up Part B Specify the direction as an angle above horizontal. Express your answer using two significant figures above horizintal Figure 1 of 1 Submit My Answers Give Up Provide Feedback Continue 5.0 cm 10 cm

Explanation / Answer

The field due to the + particel is E = k*q/r^2 = 9.0x10^9*5.0x10^-9/0.05^2 = 18000 N/C i

The field for the negative charge is 9.0x10^9*5.0x10^-9/(0.05^2 + 0.10^2) = 3600N/C

The angle = arctan(5/10) = 26.6o

So the x comp = -cos(26.6)*3600 = -3218.9N/c

y comp = -sin(26.6)*720 = -1441.3N/C

So

the field is x comp -3218.9 + 18000 = -21218.9N/c

y comp = -1441.3N/C

So

E = sqrt(21218.9^2 + 1441.3^2) = 2.12x10^3N/C

and

= arctan(-1441.3/-21218.9) = 3.88o

but since x comp is negative then = 3.88 + 180 = 183.8o

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