Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Consider the circuit shown below. You must use Mesh Analysis to answer this ques

ID: 1434036 • Letter: C

Question

Consider the circuit shown below. You must use Mesh Analysis to answer this question.

(a) Write the loop equation for the current, I1, in the left hand loop. Start at the bottom left hand corner (point a) of the loop. SIMPLIFY, BUT DO NOT SOLVE THE EQUATION!

(b) Write the loop equation for the current, I2, in the middle loop. Start at the bottom left hand corner (point b) of the loop. SIMPLIFY, BUT DO NOT SOLVE THE EQUATION!

(c) Write the loop equation for the current, I3, in the right hand loop. Start at the bottom left hand corner (point c) of the loop. SIMPLIFY, BUT DO NOT SOLVE THE EQ

Express your results in the following format:

I1_______ I2 ________ I3= _________

I1_______ I2 ________ I3= _________

I1_______ I2 ________ I3= __________

10 V 2 12 6 10 3 2 sv :59 4 8 14

Explanation / Answer

A) 5 - 2i1 - 6(i1 - i2) - 4i1 = 0

12i1 - 6i2 = 5


B) 6(i2 - i1) + 10 - 10(i2 - i3) - 8i2 =0

- 6i1 + 24i2 - 10i3 = 10

C) 10(i3 - i2) - 12i3 + 15 - 14i3 = 0


- 10i2 + 36i3 = 15

D)

12i1 - 6i2 + 0i3 = 5
- 6i1 + 24i2 - 10i3 = 10
0 i1 - 10i2 + 36i3 = 15
solving three equations,

i1 = 215/246

i2 = 75/82

i3 = 55/82