Parts: (a,b,c,d) 28.7 Begin Date: 2/29/2016 12:00.00 AM Due Date: 3/182016 10:15

Question

Parts: (a,b,c,d) 28.7 Begin Date: 2/29/2016 12:00.00 AM Due Date: 3/182016 10:15:00 AM End Date: 5/13/2016 11300:00 PM z-aris (20%) Problem 8: A solid disk of radius R m II cm lies in the y-z plane with the center at the origin. The disk carries a uniformly distributed total charge Q 35 C. Apoint P is located on the positive half of the x-axis a distance 19 cm from the origin, Refer to the diagram. where the y- and z-axes lie in the plane of the screen and the x-axis points out of the screen. otheexpertta.com artial A 25% Part (a Enter an expression for the surface charge density a in terms of the total charge and radius of the disk. Grade Summary Deductions 05 7 8 9 Submissions Attempts remaining: S 2 3 Bunts: 1 doductioe per hint. Hints remaining: Feedback: deduction per feedback. i A 25% Part Consider a thin ring of the disk of width dr the Enter an equation for the infinitesimal charge in this thin ring in terms of Q, R,r, and dr located a distancerfrom center. 25% Part (c) calculate electric potential at P, in kilovolts. ii 4 25 Part (d) the magnitude of the electric field at the point Pin units of meganewtons per coulomb.

Explanation / Answer

PART A

sigma = Q/piR^2

PARTB

dQ = sigma * 2*pi*r*dr
dQ = Q/piR^2 * (2*pi*r*dr)
dQ = 2*Q*r*dr / R^2

PART C

x = 19/100 = 0.19
R = 11/100 = 0.11

V = sigma*[ sqrt{R^2 + x^2} - x ] / 2epsilon
V = Q/piR^2 * [ sqrt{R^2 + x^2} - x ] / 2epsilon
V = Q*[ sqrt{R^2 + x^2} - x ] / (2*epsilon*pi*R^2)
V = 35e-6 * [ sqrt{0.11^2 + 0.19^2} - 0.19] / {2*8.854e-12*3.14*(0.11)^2}
V = 1536.97 V

PART D

E = sigma*[ 1 -{x/sqrt(R^2+x^2)} ] / 2epsilon
E = Q/piR^2 * [ 1 -{x/sqrt(R^2+x^2)} ] / 2epsilon
E = Q * [ 1 -{x/sqrt(R^2+x^2)} ] / (2*epsilon*pi*R^2)

E = 35e-6 * [ 1 - {0.19/sqrt(0.11^2 + 0.19^2)} ] / {2*8.854e-12*3.14*(0.11)^2}

E = 7

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