Parts a and b of the drawing show the same uniform and constant (in time) magnet

Question

Parts a and b of the drawing show the same uniform and constant (in time) magnetic field B directed perpendicularly into the screen over a rectangular region. Outside this region, there is no field. Also shown is a rectangular coil (one turn), which lies in the plane of the screen. In part a the long side of the coil (length = L) is just at the edge of the field region, while in part b the short side (width = W) is just at the edge. It is known that L/W = 2.80. In both parts of the drawing the coil is pushed into the field with the same velocity v until it is completely within the field region. The magnitude of the emf induced in the coil in part a is 0.117 V. What is its magnitude in part b?

Explanation / Answer

emf1 = B*v*L

emf2 = B*v*W

==> emf2/emf1 = W/L

emf2 = em*f1*(W/L)

= 0.117*(1/2.8)

= 0.04178 volts

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