I\'m really struggling with answering these three parts to my lab report... any
ID: 1442857 • Letter: I
Question
I'm really struggling with answering these three parts to my lab report... any help would be appreciated
A) It was stated in step B-4 that the speed of the hanging strip as it passes through the photogate is given by v=x/T. Whis is this so?
B) Which curve, the one graphed in Part A or the one graphed in Part B, gives a better valued for the aungular acceleration? Explain why this is so.
C) You have made four seperate determinations of the angular acceleration; how do they compare? Which do you think is the most accurate? Explain why this is so.
Explanation / Answer
The rate of change of position gives the velocity.
Mathematically, it is equal to
y = x / T
Because, the given graph is in the form y = mx
The differntiation ( or slope ) represents velocity
v = dy / dt = m dx/ dt
For a unit measurement of quantities, ( i'e unit mass, m = 1 etc.. )
v = x/T
This is the equation for velocity
-----------------------------------------------------------------------------------------------------------------------
The angular acceleration is found by the slope of the angular velocity-time curve.
Because, the rate of change of angular speed ( slope ) is equal to angular acceleration.
Slope = d / dt
Thus, the second graph better valued for the aungular acceleration.
--------------------------------------------------------------------------------------------------------------------------------
The least scaling of the graph values gives most accurate results. In the given graphs, the scaling of measurements
( on x- and y-axis ) in second graph are smaller units as compared to first graph. Thus, this is most accurate.