I\'m really struggling with the binary arithmetic part of my class. I don\'t und

Question

I'm really struggling with the binary arithmetic part of my class. I don't understand it the way my professor teaches it.

I need to simplify the following equations:
5. (A .B) + (!A + !B) = (each part of the equation should have a bar over everything in parentheses)
6. (A . B) + B .!C + !A . !B.!C = (the part in parentheses should have a bar over it all)
7. D +!B .!C + C .!D +!A .!B . C =
8. A . B + B .!C +!A .!C =

I would appreciate any help.

Thank you

Explanation / Answer

(A.B)'+(A'+B')' by demorgans theorem we have (AB)'= A'+B' and (A'+B')' = AB ==> AB+A'+B' // A'+AB = A'+B proven in previous question A+A'B = A+B take A as A' u get it A+B+B' = 1 6. (A . B) + B .!C + !A . !B.!C = A'+B'+B.C'+A'B'C' = A'(1+B'C')+B'+BC' ==> A'+B'+BC' = A'+B'+C' 7. D +!B .!C + C .!D +!A .!B . C = D +B' .C' + C .D' +A' .B' . C //D+CD' = D+C D+C+B'C'+A'B'C D+C(1+A'B)+B'C' = D+C+B'C' = B'+C+D 8 A . B + B .!C +!A .!C AB+C'(A+B') I THINK U FORGOT TO NEGATE B IN SECOND TERM IF IT ISNT THEN ABOVE ONE IS THE SOLUTION IF NOT AB+C'(A'+B') = AB+C'(AB)' = AB+C'

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