MasteringPhysics: HW 15: Rotational Dynamics - le Chromee https://session.master

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MasteringPhysics: HW 15: Rotational Dynamics - le Chromee https://session.masteringphysics.com/myct/itemView?assignmentProblemID=58076061&offset-prev; PHY 111 - Spring 2016 Sections 1,3 Help | Close Enhanced EOC: Problem 7.23 Resources previous | 3 of 5 | next » Part A Enhanced EOC: Problem 7.23 What is the net torque on the merry-go-round? Express your answer to three significant figures and include the appropriate units Tom and Jerry both push on the 2.80 m -m-diameter merry-go-round shown in (Figure 1). Tom pushes with a force of 47.5 N and Jerry pu shes with a force of 37.5 You may want to review ( pages 198-203) For help with math skills, you may want to review: Figure 1 |ofl Submit Hints My Answers Give Up Review Part Incorrect, One attempt remaining, Iry Again Part B 60 80° What is the net torque if Jerry reverses the direction that he pushes by 180 ° without changing the magnitude of his force? Express your answer to three significant figures and include the appropriate units err T= Value Units Submit Hints My Answers Give Up Review Part

Explanation / Answer

Given: d=2.8m
Ft=47.5N
Fj=37.5N

Call the counterclockwise direction positive

Torque is the sum of the force components tangent to the merry go round times the distance from the center of rotation.
r = 1.4m
Tom ---> 47.5*cos 30*(1.4) = 57.6 N-m
Jerry---> -37.5(cos10)(1.4) = -51.70 N-m
Total Torque = 57.6-51.70 = 5.9N-m

If Jerry reverses his force his torque becomes positive
Jerry ---> 37.5(cos10)(1.4) = 51.70 N-m
Total Torque = 57.6+51.70=109.30N-m

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