Consider the wire between the poles of the horseshoe magnets (south poles on the

Question

Consider the wire between the poles of the horseshoe magnets (south poles on the left, north poles on the right) shown in the diagram in the lab manual.

(i) For the current as shown, the direction of the force on the wire, Fm, is:

A) parallel to the current

B) up

C) antiparallel to the current

D) down

E) left

F) right

(ii) In the same setup, the system is balanced for I = 0 and xbal = 0. Then the current is turned on and the mass, m, is moved to xbal = x. If the system again balances, which of the following statements is true?

A) The torque due to the force Fm is mgx.

B) The magnitude of the force on the current-carrying wire is Fm = mg.

C) The magnitude of the force on the current-carrying wire is Fm = xIB.

Enter your answers to questions (i) and (ii) together; e.g., if the answer to question (i) is C, and to (ii), AB, enter CAB.

plug Xbal on the pow approxima counterbalance curre ce shou field sed pivot magnets DC Power supply Ammeter Fig. 6.1-The current balance. Current runs from the power supply, through the pivot, along the length of the wire, through the other pivot, through the ammeter and back into the power supply.

Explanation / Answer

Solution:

Force is perpendicular to B and I

The magnetic field B is from the North pole towards the south pole.

D .Direction of force is Down , using Fleming's left hand rule

ii) AC

Torque is the force produced * perpendicular distance from the point of action of force.

Answer: DAC

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