Show Clear and detailed calculation for all problems. DO NOT put solutions on th

Question

Show Clear and detailed calculation for all problems. DO NOT put solutions on the test paper. IT WILL NOT BE GRADED Data: V= IR; P = VI; P = VI; R = rhoL/A EPE = q delta V E = kq/r^2 y = kq/r A massive spool of copper 100 km long has a diameter of 0.5 cm. As copper has great value it is stored in a secured vault. However, a gang of thieves gets into the vault and hacks a considerable length. Tests reveal that the remaining cable has a resistance of 38 Ohm. rho = 1.73 times 10^-8 Ohm-meter for copper] Determine the length of cable stolen by the gang. Calculate the ratio of the length of cable remaining to the original length. Two charge q_1 = -15 mu C and q_2 = +20 mu C are 4.0 m apart as shown in the diagram below. Compute the work (electrostatic potential energy) that must be done to bring a third charge q_3 = +8.0 mu C from infinity to the point P, 3.0 m directly above q_1. In the figure below, if Q = 30 mu C, q = 5.0 mu C, and d = 30 cm, calculate the magnitude and direction of the electrostatic force on q

Explanation / Answer

1.

Area

A=pi*D2/4 =pi*(0.5*10-2)2/4 =1.963*10-5 m2

a)

Resistance of lost cable

RLost =pL/A

38 =(1.73*10-8)*L1/(1.963*10-5)

L=43128 m =43.1 Km

b)

Length of the remaining cable

L2 =100-43.1 =56.9 Km

=>Ratio =L2/L =56.9/100 =0.569

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