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Please show work and explain. Thanks. A mass spectrometer measures the mass of i

ID: 1452038 • Letter: P

Question

Please show work and explain. Thanks.

A mass spectrometer measures the mass of ions, by knowing their charge and the shape of the detector. If the Distance d between the entrance and exit holes is 7.50 cm and the B field has a value of 1.25 T, in the apparatus to the right, What velocity is needed to accelerate an O_2^+ with a mass of 32.0 u (u = atomic mass unit) and have it be detected? What potential difference is needed to reach this velocity? What potential is needed to detect H^+ with mass of 1.00 u? If this same potential from part c was used for the O^+_2 molecule, and the B field was turned on a split second after the it left the capacitor (thus allowing full cyclotron motion), what would the frequency of oscillation be?

Explanation / Answer


a)

In a magnetic field

Fb = Fc


q*V*B = m*v^2/r


r = mv/qB

d = 2r = 2*mv/qB


0.075 = 2*32*1.66054*10^-26*v/(1.6*10^-19*1.25)


v = 1.411*10^4 m/s


___________

b)

work done = 0.5*m*v^2


dV*q = 0.5*m*v^2

dV*1.6*10^-19 = 0.5*32*1.66054*10^-26*(1.411*10^4)^2


dV = 330 V


++++++++++++++++

c


d = 2r = 2*mv/qB


0.075 = 2*1*1.66054*10^-26*v/(1.6*10^-19*1.25)


v = 4.52*10^5 m/s

dV*1.6*10^-19 = 0.5*1*1.66054*10^-26*(4.52*10^5)^2


dV = 10601.7 V


++++++++++++++

d)


r = mv/qB

T = 2pir/v = 2*pi*m*v/q*B*v = 2*pi*m/qB

f = 1/T = qB/(2*pi*m)

f = (1.6*10^-19*1.25)/(2*pi*32*1.66054*10^-26)


f = 59903 Hz