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In Fig. 35-4, assume two waves of light in air, of wavelength 681 nm, are initia

ID: 1453784 • Letter: I

Question

In Fig. 35-4, assume two waves of light in air, of wavelength 681 nm, are initially in phase. One travels through a glass layer of index of refraction n1 = 1.58 and thickness L. The other travels through an equally thick plastic layer of index of refraction n2 = 1.38. What is the smallest value L in meters should have if the waves are to end up with a phase difference of 6.42 rad?

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Explanation / Answer

L = (n + (6.42/6.28))681/1.58

L = n x 681/1.38

so (n + (6.42/6.28))681/1.58 = n x 681/1.38

=> n = 7.0538

=> L = 3480.9 nm = 3.481 um