Consider the molecule C6H12 which is ionized by removing one electron and accele
ID: 1455955 • Letter: C
Question
Consider the molecule C6H12 which is ionized by removing one electron and accelerated to a speed of 7500 km/s.A. As it passed through a region of uniform magnetic and electric field(E and B are perpendicular) what magnetic field is necessary for the condition of no deflection( zero Lorentz force) given and electric field of 550,000 V/m?
B. If it then enters a region of space with a uniform magnetic field of 4.0 T and no electric field what is the radius of the cyclotron orbit? Consider the molecule C6H12 which is ionized by removing one electron and accelerated to a speed of 7500 km/s.
A. As it passed through a region of uniform magnetic and electric field(E and B are perpendicular) what magnetic field is necessary for the condition of no deflection( zero Lorentz force) given and electric field of 550,000 V/m?
B. If it then enters a region of space with a uniform magnetic field of 4.0 T and no electric field what is the radius of the cyclotron orbit?
A. As it passed through a region of uniform magnetic and electric field(E and B are perpendicular) what magnetic field is necessary for the condition of no deflection( zero Lorentz force) given and electric field of 550,000 V/m?
B. If it then enters a region of space with a uniform magnetic field of 4.0 T and no electric field what is the radius of the cyclotron orbit?
Explanation / Answer
A) Here, v = E/B
=> 7.5 * 106 = 550,000/B
=> B = 0.0733 T --------------------------> magnetic field necessary for the condition of no deflection
B) Here, r = mv/qB
=> r = (0.084 * 7.5 * 106) /(1.6 * 10-19 * 4 * 6.023 * 1023)
= 1.634 m -------------------> the radius of the cyclotron orbit