Claflin University PHYS 2 x C WWW sapling learning.com /ibiscms/mod/ibis/view.ph
ID: 1458165 • Letter: C
Question
Claflin University PHYS 2 x C WWW sapling learning.com /ibiscms/mod/ibis/view.php?id-199504 Norton Sapling Sapling Learning Claflin University PHYS 20 Fall15 Ekpenuma Activities and Due Dates HW: W My Assignment O 5/2015 11:55 PM A 7.9/10 4/2015 05:45 PM Gradebook Attempts Score Print Calculator Periodic Table 00 Questi 2 of The graph shows the component of a force acting on an object, in newtons, versus the position of the object, in meters. Find the work done by the force over the specified intervals of displacement: a) x 0.0 m, 4.9 m 00 3.3 Number C) 14 m, xf E 7.7 m: Number Previous 3 Give Up & View Solution Check Answer Next SExit Search the web and Window Resources Assignment Information Available From: 2015 02:00 PM 11/5/2015 11:55 PM Due Date: Points Possible: 10 Grade Category: Graded Description: Policies: Homework heck y up on any question You can keep trying to answer each question until you get it right or give up. You lose 5% of the points available to each answer O eTextbook OHelp With This Topic Web Help & Videos O Technical Support and Bug Reports Logo 639 PMExplanation / Answer
area of the force versus distance graph gives the work done
area of the graph between 0 to 4.9 m
area = 4 * 4.9 + 0.5 * 1 * 4 + (4.9 - 3) * 4
area = 29.2
W = 29.2 J
area of graph between 6 to 13.3 m
area = 0.5 * 3 * 8 - 0.5 * 2 * 6 - (13.3 - 11) * 6
area = -7.8
W = -7.8 J
area of graph between 14 to 17.7 m
area = -0.5 * 4 * 2 - (17.7 - 14) * 2
area = -11.4
W = -11.4 J