Claflin University PHYS 2 x www.saplinglearning.com x Physics question I Chegg.
ID: 1459165 • Letter: C
Question
Claflin University PHYS 2 x www.saplinglearning.com x Physics question I Chegg. X C WWW sapling learning.com /ibiscms/mod/ibis/view.php?id-1995045 Norton a SHARE VIA THIS PAGE IS sapling learning A 6.33-kg object constrained to move along the x-axis is subjected to a time-varying force as shown on the graph below. Find the change in the object's velocity over the specified time intervals. a) Between t 0 s and tf E 4.01 s Force vs. Time Number Av b) Between ti 5.25 s and tf 10 s (N) Number Av 6 8 10 12 14 16 18 20 c) Between ti 10 s and tf 6.9 s t (s) Number Av F A Previous 3 Give Up & View Solution Check Answer Next Exit Hin Search the web and Windows 11/7/2015Explanation / Answer
area of the force vs time graph gives the impules and,
impulse = change in momentum
impulse between time 0 - 4.01 sec
impulse = 12 * 4 .01
12 * 4.01 = mass * change in velocity
12 * 4.01 = 6.33 * change in velocity
change in velocity = 7.602 m/s
from time 5.25 to 10 sec
impulse = 12 * (7 - 5.25) + 0.5 * 12 * (10 - 7)
12 * (7 - 5.25) + 0.5 * 12 * (10 - 7) = 6.33 * change in velocity
change in velocity = 6.161 m/s
from time 10 to 16.9 sec
impulse = 0.5 * 6 * 4 + 0.5 * 3 * (16.9 - 14) + 3 * (16.9 - 14)
0.5 * 6 * 4 + 0.5 * 3 * (16.9 - 14) + 3 * (16.9 - 14) = 6.33 * change in velocity
change in velocity = 3.9573 m/s