Tom and Jerry both push on the 3.00-m-diameter merry-go-round shown in (Figure 1

Question

Tom and Jerry both push on the 3.00-m-diameter merry-go-round shown in (Figure 1) . Tom pushes with a force of 49.0 N and Jerry pushes with a force of 35.5 N .

Part A

What is the net torque on the merry-go-round?

Express your answer to three significant figures and include the appropriate units.

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Part B

What is the net torque if Jerry reverses the direction that he pushes by 180 without changing the magnitude of his force?

Express your answer to three significant figures and include the appropriate units.

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Explanation / Answer

Consider here the counterclockwise direction as positive

Here the torque is sum of the force components to the merry go roud times the distance from the center of rotation

Therefore we can radisu as(r) =1.5 m, because the diamter is 3m

Torque acting on the tom ttom = 49cos30*1.5 =63.652N.m

Torque acting on the jerry tjerry =-35.5*sin(10)*1.5 =-52.441N.m

now the total torque acting is given b t =63.652 -52.441 =11.210N.m

What is the net torque if Jerry reverses the direction that he pushes by 180 without changing the magnitude of his force is given by

then Torque acting on the jerry tjerry =35.5*sin(10)*1.5 =52.441N.m becoems positive

now the total torque acting is given b t =63.652 + 52.441 =11.210N.m=116.093N.m

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