Mastering Physics: Ch 07 X o Session ring physics.com assignment Problem 5147608
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Question
Mastering Physics: Ch 07 X o Session ring physics.com assignment Problem 51476084&offset-next; /myct/itemView? Signed in as Chris Lowther I Help I Close A COLLEGE PHYS-203 fa2015 Ch 07 HW (Part 2) Three-Block Inelastic Collision previous 7 of 19 next Three-Block Inelastic Collision Part A A block of mass m1 1.80 kg moving at v1 20 m/s undergoes Find the ratio of the velocity v2 of the two-block system after the first collision to the velocity vi of the block of mass m1 before the collision a completely inelastic collision with a stationary block of mass m2 0.800 kg. The blocks then move, stuck together, at speed v2. After Express your answer numerically using three significant figures. a short time, the two-block system collides inelastically with a third block, of mass m3 2.80 kg which is initially at rest. The three blocks then move, stuck together, with speed (Figure 1 Assume that the blocks slide without friction. Submit Hints My Answers Give Up Review Part Figure 1 of 1 Part B Find the ratio of the velocity v3 of the three-block system after the second collision to the velocity vi of the block of mass m1 before the collisions Express your answer numerically using three significant figures. v2 Submit Hints My Answers Give Up Review Part Provide Feedback Continue 3:07 PM Ask me anything 11/8/2015Explanation / Answer
here momentum remain conserve
m1v1 = (m1+m2)v2 ....(1)
v2/v1 = m1/(m1+m2) = 1.8 / (1.8 + 0.8 ) =
v2/v1 = 0.69
now two block collide with 3rd block here also momentum conserve
(m1+m2)v2 = (m1+m2+m3)v3
from equation 1
(m1+m2)v2 = m1v1
m1v1 = (m1+m2+m3)v3
v3/v1 = m1/(m1+m2+m3)
v3/v1 = 1.8 / (1.8 + .8 + 2.8)
v3/v1 = 0.33