Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

The solutions in the arms of a U-tube are separated at the bottom of a selective

ID: 14623 • Letter: T

Question


The solutions in the arms of a U-tube are separated at the bottom of a selectively permeable membrane. The membrane is permeable to sodium chloride and water but not glucose. Initially, the volume in both arms is the same.

Side A is filled with a solution of 0.4 M glucose and 0.5 M sodium chloride

Side B is filled with a solution containing 0.* M glucose and 0.4 M sodium chloride.

At the beginning of the experiment,
a) side A is hypotonic to side B.
b) side A is hypertonic to side B with respect to glucose.
c) side A is hypotonic to side B with respect to sodium chloride.
d) side A is isotonic to side B.

Part two

If you exame side A agter 3 days, you should find?

a) a decrease in the concentration if NaCl and glucose and in increase in the water level.
b) no change in the concentration of NaCl and glucose and an increase in the water level.
c) a decrease in the concentration of NaCl and a decrease in the water level.
d) a decrease in the concentration of NaCl an increase in water level and no change in the concentration of glucose.









Explanation / Answer

At the beginning of the experiment,

b) side A is hypertonic to side B with respect to glucose.

Reason: High Concentration of A.

If you exame side A agter 3 days, you should find?

a) a decrease in the concentration if NaCl and glucose and in increase in the water level.

Reason: The water will leave the B side and go through the membrane to the higher concentration side (A). Therefore, the A side will have a water level increase in which the water dilutes the concentration on NaCl.