The figure shows a 19-cm-diameter loop in three different magnetic fields. The l

Question

The figure shows a 19-cm-diameter loop in three different magnetic fields. The loop's resistance is 0.15

Part A

In (Figure 1)(https://session.masteringphysics.com/problemAsset/1385988/6/34.EX11a.jpg) , what are the size and direction of the induced current?

Express your answer to two significant figures and include the appropriate units.

Part B

Part C

In (Figure 2)(https://session.masteringphysics.com/problemAsset/1385988/6/34.EX10b.jpg) , what are the size and direction of the induced current?

Express your answer to two significant figures and include the appropriate units.

Part D

Part E

In (Figure 3)(https://session.masteringphysics.com/problemAsset/1385988/6/34.EX10c.jpg) , what are the size and direction of the induced current?

Express your answer to two significant figures and include the appropriate units.

Part F

a.The loop current direction is ccw. b.There is no induced current. c.The loop current direction is cw.

Part C

In (Figure 2)(https://session.masteringphysics.com/problemAsset/1385988/6/34.EX10b.jpg) , what are the size and direction of the induced current?

Express your answer to two significant figures and include the appropriate units.

Part D

a.The loop current direction is ccw. b.The loop current direction is cw. c.There is no induced current.

Explanation / Answer

part A )

e = dphi/dt = AdB/dt

dB/dt = 0.5 T/s

A = pi*d^2/4= pi * (19*10^-2)^2/4

I = e/R = 9.5 x 10^-2 A

part b )

c.The loop current direction is cw.

part c )

dB/dt = 0.5 T/s

A = pi*d^2/4= pi * (19*10^-2)^2/4

I = e/R = 9.5 x 10^-2 A

part d )

b.The loop current direction is cw.

part e )

phi = BA costheta

rod is perpendicular to field

so theta = 90 degree

phi = 0

e = 0

I = 0

part f )

b.There is no induced current

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---