Please help, thanks. IN ALL NUMERICAL PRE-LAB QUESTIONS: answers must be compute
ID: 1464911 • Letter: P
Question
Please help, thanks.
IN ALL NUMERICAL PRE-LAB QUESTIONS: answers must be computed to three (3) significant digits. If the answer is 1.55 and you enter 1.5 or 1.6,ll be marked as incorrect
2. +-5 points Two paraepates (as in procedure 2) are parallel to the floor, distance 3.98 cm. The difference in potential between the plates is 340 V, with the upper plate at the higher potential. Assume the plates are very large (so the electric field is approximately straight lines), and no other charges are nearby a) The direction of the electric field outside of the plates and between the plates is O outside: zero, between: from positive to negative O outside: upward from the positive plate, downward from the negative plate; between: from negaitve to positive O outside: downward from the positive plate, upward from the negative plate; between: from positive to negative outside: upward from the positive plate, downward from the negative plate; between: from positive to negative outside: zero, between: from negative to positive O outside: downward from the positive plate, upward from the negative plate; between: zero O outside: downward from the positive plate, upward from the negative plate; between: from negative to positive O outside: upward from the positive plate, downward from the negative plate; between: zero O outside: zero; between: zero b) An electron (mass 9.11x10-31 kg, charge 1.60x10-19 C) is placed half-way between the plates. Find the magnitude of the force felt by the electron at this point. c) Suppose the electron is released from rest at the negative plate. Find the speed of the electron when it arrives at the positive plate m/s d) For parallel plates, what is the shape of the equipotential lines and electric field lines E: straight lines from the positive to negative plate; equipotential lines: lines parallel to the plates O E: circles parallel to the plates; equipotential lines: lines parallel to the plates 0 E: lines parallel to the plates; equipotential lines: straight lines from the negative to positive plate 0 E: straight lines from the negative to positive plate; equipotential lines: lines parallel to the plates E: straight lines from the negative to positive plate; equipotential lines: circles parallel to the plates E:straight lines from the negative to positive plate; equipotential lines: straight lines from the negative to positive plate E: lines parallel to the plates; equipotential lines: lines parallel to the plates E: straight lines from the positive to negative plate; equipotential lines: circles parallel to the plates E: lines parallel to the plates; equipotential lines: circles parallel to the plates 0 E: straight lines from the positive to negative plate; equipotential lines: straight lines from the negative to positive plate 0 E: circles parallel to the plates; equipotential lines: circles parallel to the plates E: circles parallel to the plates; equipotential lines: straight lines from the negative to positive plate e) An electron is moved slowly from the negative plate to the positive plate. As the electron approaches the positive plate O the magnitude of the electric force on the electron decreases; the direction of the electric force on the electron changes the magnitude of the electric force on the electron increases; the direction of the electric force on the electron is unchanged O the magnitude of the force on the electron is unchanged; the direction of the electric force on the electron is unchanged the magnitude of the electric force on the electron increases; the direction of the electric force on the electron changes the magnitude of the electric force on the electron is unchanged; the direction of the electric force on the electron changes O the magnitude of the electric force on the electron decreases; the direction of the electric force on the electron is unchangedExplanation / Answer
a) outside zero, between from positive to negative
b) E= V/d = 340/3.98 x 10-2 = 8.54 x 103 V/m
F = q E = 1.6 x 10-19 x 8.54 x 103 = 1.37 x 10-15 N
c) a = F/m = 1.5 x 1015m/s2
v =(2ax)1/2 = 1.09 x 106 m/s
d) E: straight lines from positve to negative and equipotential lines parallel to the plates
e) the magnitude of electric force is unchanged, direction of electric force is unchanged