Please help, need those answers of these 2 problems Safari File Edit View Histor

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Please help, need those answers of these 2 problems

Safari File Edit View History Bookmarks window Help west.cengagenow.com OWLv2 Online teaching and learning resource from Cengage Learning Specific Heats Find the volume of the parallelepiped determined by the vectors a, b.... Assignment 12 Energy Part 2 (Exam 3) Review Topics Use the References to access important values if needed for this question 1 . Thermochemical Stoichiometry 2. Coffee Cup Calorimetry: Specific... 3. Coffee Cup Calorimetry Solution... 1 pts 1 pts 1 pts 2req When a solid dissolves in water, the solution may become hotter or colder. The dissolution enthalpy (dissolving) can be determined using a coffee cup calorimeter 2req Thermometer Cardboard or Styrofoam lid In the laboratory a general chemistry student finds that when 2.11 g CuCl2(s) is dissolved in 105.30 g water, the tempcrature of the solution increases from 25.61 to 27.41 . 4. Manipulating Themochemical E.. 1pts 2req The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.81 J/°C. 5. Hess's Law: Two Reactions Nested Styrofoam cups 1 pts 2req Based on the student's observation, calculate the dissolution enthalpy of CuCl2(s) in kJ/mol 6. Formation Enthalpy: Reaction E... 1pts 2req 7. Formation Enthalpy: Calculate fr... 1 pts 2req 8. Thermochemical Expressions: 1 pts 2req Reaction occurs in solution. Assume the specific heat capacity of the solution is equal to the specific heat capacity of water AgisH = kJ/mol Submit Answer Retry Entire Group 4more group attempts remaining Progress 1/8 groups Due Nov 19 at 10:50 PM Next Previous 18

Explanation / Answer

-Qsalt = Qsurroundings

Qsalt = mw*Cw*(Tf-Tw) + CCal*(Tf-Tw)

-Qsalt = 105.3*4.184*(27.41-25.61) + 1.81*(27.41-25.61)

Qsalt = -796.293 J

mol of CuCl2 = mass/MW = 2.11/796.293 = 0.00264 mol

Hsoln = Qsalt/mol = -796.293 /0.00264

Hsoln = --301626.1 J/mol

Hsoln = -301.63 kJ/mol

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